The answer will appear below; Always use the upper case for the first character in the element name and the lower case for the second character. Privacy Policy, and Terms and Conditions. Compound states [like (s) (aq) or (g)] are not required. Examples: Fe, Au, Co, Br, C, O, N, F.     Compare: Co - cobalt and CO - carbon monoxide, To enter an electron into a chemical equation use {-} or e. To enter an ion specify charge after the compound in curly brackets: {+3} or {3+} or {3}. Balanced Equation. Which is the proper way to balance the equation Ca(OH)2 + H3PO4 → Ca3(PO4)2 + H2O? The answer will appear below, Always use the upper case for the first character in the element name and the lower case for the second character. Also known as a synthesis reaction. No claim to original U.S. Gov't works. Enter either the number of moles or weight for one of the compounds to compute the rest. Copyright (c) 2013 Thatcher Development Software, LLC. Direct link to this balanced equation: Instructions on balancing chemical equations: Enter an equation of a chemical reaction and click 'Balance'. Click here to contact Greg Thatcher, 5 K4Fe(CN)6 + 43 KMnO4 + 164 HCl = 63 KCl + 5 FeCl3 + 43 MnCl2 + 30 CO2 + 30 NO + 82 H2O, 5K4Fe(CN)6 + 43KMnO4 + 164HCl = 63KCl + 5FeCl3 + 43MnCl2 + 30CO2 + 30NO + 82H2O, 5Fe(s) + 2KMnO4(aq) + HCl(aq) = 5 FeCl2 (aq) + 2 MnCl2(aq) + 2KCl (aq) + H2O(l), 5Fe(s) + 2KMnO4(aq) + 16HCl(aq) = 5FeCl2(aq) + 2MnCl2(aq) + 2KCl(aq) + 8H2O(l), 5Fe(s) + 2KMnO4(aq) + HCl(aq) = 5 FeCl2 (aq) + 2 MnCl2(aq) + 2KCl (aq) + H2O(l), 5Fe + 2KMnO4 + HCl= 5 FeCl2 + 2 MnCl2 + 2KCl + H2O, 5Fe + 2KMnO4 + 16HCl = 5FeCl2 + 2MnCl2 + 2KCl + 8H2O, Fe(CO)5 + 2PF3 + H2 = Fe(CO)2(PF3)2(H)2 + 3CO, 5Cd(s)+ Bi(CH3COO)5(aq) = Bi(s) + 5Cd(CH3COO)(aq), 5Cd(s) + Bi(CH3COO)5(aq) = Bi(s) + 5Cd(CH3COO)(aq), 14S2- + 2MnO4-1 + 16H+ = 8H2O + Mn2 + 28S, 5Fe ++ +MnO4- + 8H + = 5Fe +++ + Mn ++ + 4H2O, 5Fe++ + MnO4- + 8H+ = 5Fe+++ + Mn++ + 4H2O, I2 + 2KMnO4 + 2H2SO4 = 2MnSO4 + 2KIO3 + 2H2O, 5 OH- + Al + VO2+ = Al(OH)3 + V(OH)2 + O2, 3OH- - Al + 3VO2+ = -1Al(OH)3 + 3V(OH)2 + 3O2, 5Fe(CO)5 + 8PF3 + 6H2=Fe(CO)2(PF3)2(H)2+CO, 5 Na2C2O4(aq) +2 KMnO4(aq) +16 HCl(aq)=10 CO2(g)+2 MnCl2(aq)+8 H2O(l)+ 2 KCl(aq)+10 NaCl(aq), 5Na2C2O4(aq) + 2KMnO4(aq) + 16HCl(aq) = 10CO2(g) + 2MnCl2(aq) + 8H2O(l) + 2KCl(aq) + 10NaCl(aq), 5K2C2O4(aq)+8H2SO4(aq)+2KMnO4(aq) =2MnSO4(aq)+10CO2(aq)+8H2O(l)+ 6K2SO4(aq), 5K2C2O4(aq) + 8H2SO4(aq) + 2KMnO4(aq) = 2MnSO4(aq) + 10CO2(aq) + 8H2O(l) + 6K2SO4(aq), 5MnCO3(S) +6Al +3O2 = 5Mn + 4Al2O3(S) + 5CO2, MnCO3(S) + 2Al + O2 = Mn + Al2O3(S) + CO2, 5S + 6KNO3 + 2CaCO3 = 2K2SO4 + CaSO4 + CO2 + 2N2, 5S + 6KNO3 + 2CaCO3 = 3K2SO4 + 2CaSO4 + 2CO2 + 3N2, 5 C2H5OH(aq) + 2 KMnO4(aq) + 3 H2SO4(aq) = 5 C2H4O(aq) + 2 MnSO4(aq) + K2SO4(aq) + 8 H2O(l), 5C2H5OH(aq) + 2KMnO4(aq) + 3H2SO4(aq) = 5C2H4O(aq) + 2MnSO4(aq) + K2SO4(aq) + 8H2O(l), 5 FeCl2 + 8 HCl + KMnO4 = 5 FeCl3 + MnCl2 + 4 H2O + KCl, 5FeCl2 + 8HCl + KMnO4 = 5FeCl3 + MnCl2 + 4H2O + KCl, 5SO2 + 2KMnO4 + 2H2O = 2MnSO4 + K2SO4 + 2H2SO4, 5KI + 2KMnO4 + HCl =5I2 + 2MnCl2 + KCl + H2O, 10KI + 2KMnO4 + 16HCl = 5I2 + 2MnCl2 + 12KCl + 8H2O, 5Na2C2O4(aq) + 2KMnO4(aq) + 8H2SO4(aq) = 2MnSO4(aq) + 10CO2(g) + 8H2O(l) + 5Na2SO4(aq) + K2SO4(aq), 5Na2C2O4(aq) + 2KMnO4(aq) + 8H2SO4(aq) = 2MnSO4(aq) + 10CO2(g) + 8H2O(l) + 5Na2SO4(aq) + K2SO4(aq), 5 Zn + 2 MnO4- + 16 H+= 5 Zn2+ + 2 Mn2+ + 8 H2O, 26Zn + 2MnO4- + 16H+ = 13Zn2+ + Mn2+ + 8H2O, 5H2C2O4 + 2KMnO4 - 4H2O = 10CO2 + 2MnO + 2KOH, 5Na2SO3 + 2KMnO4 + 3H2SO4 = 5Na2SO4 + 2MnSO4 + K2SO4 + 3H2O, Bi(NO3)3*5H2O+H2O2+RuCl3+NaOH=Bi2Ru2O7+NaNO3+NaCl+H2O. C + O2 = CO2. Reaction stoichiometry could be computed for a balanced equation.

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